Czwarte zadanie
adres: http://www.pythonchallenge.com/pc/def/linkedlist.html
na tej stronie widzimy tylko jedno słowo: linkedlist.php. Idźmy tam 🙂 http://www.pythonchallenge.com/pc/def/linkedlist.php
tytuł strony: follow the chain
podpowiedź: ze źródła strony
<!-- urllib may help. DON'T TRY ALL NOTHINGS, since it will never end. 400 times is more than enough. -->
W źródle widzę też, że obrazek jest linkiem.
rozwiązanie:
Klikam w obrazek. Zostaję przekierowana na
http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=12345
Strona mówi mi tylko:
and the next nothing is 44827.
Spróbuję użyć urllib i zobaczę gdzie mnie zaprowadzi.
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
| import urllib, re | |
| param = str(12345) | |
| while(True): | |
| url = "http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=" + param | |
| page_content = urllib.urlopen(url).read() | |
| print page_content | |
| param = re.findall("nothing is (\d+)", page_content)[0] |
w pewnym momencie dostaję:
and the next nothing is 54249 and the next nothing is 29247 and the next nothing is 13115 and the next nothing is 23053 and the next nothing is 3875 and the next nothing is 16044 Yes. Divide by two and keep going.
Zmodyfikowałam kod i lecimy od nowa:
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
| import re | |
| import urllib | |
| param = str(12345) | |
| while (True): | |
| try: | |
| url = "http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=" + param | |
| page_content = urllib.urlopen(url).read() | |
| print page_content | |
| param = re.findall("nothing is (\d+)", page_content)[0] | |
| except IndexError: | |
| param = str(int(param) / 2) |
Dzięki wyszukiwaniu tylko tego co stoi przy nothing udało mi się uniknąć kolejnej pułapki
and the next nothing is 49574 and the next nothing is 82682 There maybe misleading numbers in the text. One example is 82683. Look only for the next nothing and the next nothing is 63579
Nagle pośród tego łańcucha niczego pojawia się inny komunikat:
peak.html
Gdybym nie patrzyła, to mogłabym to pominąć, więc zmodyfikuję trochę kod i pędzę dalej:
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
| import re | |
| import urllib | |
| param = str(12345) | |
| while (True): | |
| try: | |
| url = "http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=" + param | |
| page_content = urllib.urlopen(url).read() | |
| print page_content | |
| param = re.findall("nothing is (\d+)", page_content)[0] | |
| except IndexError: | |
| if page_content.endswith('.html'): | |
| break | |
| param = str(int(param)/2) |
adres kolejnej zagadki: http://www.pythonchallenge.com/pc/def/peak.html